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Mathematics
Mathematics
Problem
Let
f
(
x
)
=
∣
x
−
1
∣
f(x) = |x-1|
f
(
x
)
=
∣
x
−
1∣
. Then (A)
f
(
x
2
)
=
(
f
(
x
)
)
2
f(x^2) = (f(x))^2
f
(
x
2
)
=
(
f
(
x
)
)
2
(B)
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
f(x+y) = f(x) + f(y)
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
(C)
f
(
∣
x
∣
)
=
∣
f
(
x
)
∣
f(|x|) = |f(x)|
f
(
∣
x
∣
)
=
∣
f
(
x
)
∣
(D) None of these.
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