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Mathematics
Mathematics
Problem
The condition that the circle
(
x
−
3
)
2
+
(
y
−
4
)
2
=
r
2
(x-3)^2 + (y-4)^2 = r^2
(
x
−
3
)
2
+
(
y
−
4
)
2
=
r
2
lies entirely within the circle
x
2
+
y
2
=
R
2
x^2 + y^2 = R^2
x
2
+
y
2
=
R
2
is a.
R
+
r
≤
7
R + r \le 7
R
+
r
≤
7
b.
R
2
+
r
2
<
49
R^2 + r^2 < 49
R
2
+
r
2
<
49
c.
R
2
−
r
2
<
25
R^2 - r^2 < 25
R
2
−
r
2
<
25
d.
R
−
r
>
5
R - r > 5
R
−
r
>
5
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