Physics

Physics

Problem

Coal releases about 3.0×107 J kg−13.0\times10^{7}\,\mathrm{J\,kg^{-1}} when burnt, whereas the fission of 235 ⁣U^{235}\!\mathrm{U} releases approximately 200 MeV200\,\mathrm{MeV} per nucleus. a. (i) Derive an expression for the ratio mcoalmU\dfrac{m_{\text{coal}}}{m_{\text{U}}} of the masses of coal and 235 ⁣U^{235}\!\mathrm{U} that would yield the same total energy output, starting from the given microscopic and macroscopic data. b. (ii) Using 1 eV=1.602×10−19 J1\,\mathrm{eV}=1.602\times10^{-19}\,\mathrm{J} and Avogadro number 6.022×1023 mol−16.022\times10^{23}\,\mathrm{mol^{-1}}, calculate numerically the mass of coal required to produce the same energy as 1.0 kg1.0\,\mathrm{kg} of 235 ⁣U^{235}\!\mathrm{U} fissioned completely. c. (iii) Comment on two logistic or environmental advantages that the result in part (ii) confers on nuclear power stations over conventional coal-based stations.

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