Mathematics

Problem

Let

f\!:\!\mathbb{R}\setminus\{1\}\to\mathbb{R}

be defined by

f(x)=\dfrac{2x}{x-1}

. Choose the correct statement about the surjectivity of

f

. a)

f

is not onto, because

y=0

has no pre-image in

\mathbb{R}\setminus\{1\}

. b)

f

is not onto, because

y=2

has no pre-image in

\mathbb{R}\setminus\{1\}

. c)

f

is onto

\mathbb{R}

. d)

f

is not onto, because

y=1

has no pre-image in

\mathbb{R}\setminus\{1\}