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Problem
Problem
If
x
k
=
(
sec
θ
)
1
2
k
+
(
tan
θ
)
1
2
k
x_k = (\sec \theta)^{\frac{1}{2^k}} + (\tan \theta)^{\frac{1}{2^k}}
x
k
=
(
sec
θ
)
2
k
1
+
(
tan
θ
)
2
k
1
and
y
k
=
(
sec
θ
)
1
2
k
y_k = (\sec \theta)^{\frac{1}{2^k}}
y
k
=
(
sec
θ
)
2
k
1
–
(
tan
θ
)
1
2
k
(\tan \theta)^{\frac{1}{2^k}}
(
tan
θ
)
2
k
1
, then value of
3
y
n
∏
k
=
0
n
(
x
k
)
3y_n \prod_{k=0}^{n} (x_k)
3
y
n
∏
k
=
0
n
(
x
k
)
is equal to
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