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Mathematics
Mathematics
Problem
Let
ω
≠
1
\omega \neq 1
ω
=
1
be a complex cube root of unity. If
(
3
−
3
ω
+
2
ω
2
)
4
n
+
3
+
(
2
+
3
ω
−
3
ω
2
)
4
n
+
3
+
(
−
3
+
2
ω
+
3
ω
2
)
4
n
+
3
=
0
(3 - 3\omega + 2\omega^2)^{4n+3} + (2 + 3\omega - 3\omega^2)^{4n+3} + (-3 + 2\omega + 3\omega^2)^{4n+3} = 0
(
3
−
3
ω
+
2
ω
2
)
4
n
+
3
+
(
2
+
3
ω
−
3
ω
2
)
4
n
+
3
+
(
−
3
+
2
ω
+
3
ω
2
)
4
n
+
3
=
0
, then possible value(s) of
n
n
n
is (are) a. 1 b. 2 c. 3 d. 4
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