Classical Electrodynamics · Problem 6.5

Plane Electromagnetic Waves and Wave Propagation — John David Jackson

Physics — E&M · electromagnetic-momentum-static-fields

Problem

A localized electric charge distribution produces an electrostatic field, E=−∇Φ\mathbf{E} = -\nabla\Phi. Into this field is placed a small localized time-independent current density J(x)\mathbf{J}(\mathbf{x}), which generates a magnetic field H\mathbf{H}. (a) Show that the momentum of these electromagnetic fields, (6.117), can be transformed to Pfield=1c2∫ΦJ d3x\mathbf{P}_{\text{field}} = \frac{1}{c^2}\int \Phi \mathbf{J}\, d^3x provided the product ΦH\Phi\mathbf{H} falls off rapidly enough at large distances. How rapidly is ``rapidly enough''? (b) Assuming that the current distribution is localized to a region small compared to the scale of variation of the electric field, expand the electrostatic potential in a Taylor series and show that Pfield=1c2E(0)×m\mathbf{P}_{\text{field}} = \frac{1}{c^2}\mathbf{E}(0) \times \mathbf{m} where E(0)\mathbf{E}(0) is the electric field at the current distribution and m\mathbf{m} is the magnetic moment, (5.54), caused by the current. (c) Suppose the current distribution is placed instead in a uniform electric field E0\mathbf{E}_0 (filling all space). Show that, no matter how complicated is the localized J\mathbf{J}, the result in part a is augmented by a surface integral contribution from infinity equal to minus one-third of the result of part b, yielding Pfield=23c2E0×m\mathbf{P}_{\text{field}} = \frac{2}{3c^2}\mathbf{E}_0 \times \mathbf{m} Compare this result with that obtained by working directly with (6.117) and the considerations at the end of Section 5.6.

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