An experimenter finds that water vapor is 0.53\% dissociated at a temperature of 2000 K and a pressure of 105 Pa. Raising the temperature to 2100 K and keeping the pressure constant leads to a dissociation of 0.88\%. That is, an initial mole of H2O remains as 0.9947 moles at 2000 K or as 0.9912 moles at 2100 K after the reaction comes to completion. Calculate the heat of reaction of the dissociation of water at P=105 Pa and T≈2050 K.
Answer: ΔH=2.7×105 J/mole