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Mathematics
Problem
Complete Pythagoras Theorem (CPT:). We will prove CPT using similarity. In
△
A
B
C
\triangle ABC
△
A
B
C
we have
∠
A
=
90
\angle A = 90
∠
A
=
90
,
A
D
‾
⊥
B
C
‾
\overline{AD} \perp \overline{BC}
A
D
⊥
B
C
. Let
A
B
=
c
,
B
C
=
a
,
C
A
=
b
,
B
D
=
x
,
D
C
=
y
,
A
D
=
h
AB = c, BC = a, CA = b, BD = x, DC = y, AD = h
A
B
=
c
,
B
C
=
a
,
C
A
=
b
,
B
D
=
x
,
D
C
=
y
,
A
D
=
h
.
m
∠
B
=
u
m\angle B = u
m
∠
B
=
u
and
m
∠
C
=
v
m\angle C = v
m
∠
C
=
v
.
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