Mathematics

Mathematics

Problem

The revenue, in thousand rupees, obtained by selling a product at a price of ₹pp per unit is given by R(p)=1000p−50p2R(p)=1000p-50p^2 for 0≤p≤200\le p\le 20. a. (i) Find the critical price(s) of RR in the given interval. b. (ii) Determine the subintervals of the given domain on which the revenue increases with price. c. (iii) If the current price is ₹8, should the firm raise the price or lower it to increase revenue? Give one reason.

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