Consider I=∫ax2+bx+cdx where a>0 and b2−4ac>0. Which of the following gives the correct antiderivative of I?
a) 2b2−4ac1ln2ax+b+b2−4ac2ax+b−b2−4ac+C
b) b2−4ac2tan−1(b2−4ac2ax+b)+C
c) b2−4ac1ln2ax+b+b2−4ac2ax+b−b2−4ac+C
d) b2−4ac1ln2ax+b−b2−4ac2ax+b+b2−4ac+C