Mathematics

Mathematics

Problem

The vertices of a triangle are (0, 0), (1, 0) and (0, 1). Then excentre opposite to (0, 0) is a. (−12,1+12)\left(-\frac{1}{\sqrt{2}}, 1 + \frac{1}{\sqrt{2}}\right) b. (1+12,1+12)\left(1 + \frac{1}{\sqrt{2}}, 1 + \frac{1}{\sqrt{2}}\right) c. (1+12,1−12)\left(1 + \frac{1}{\sqrt{2}}, 1 - \frac{1}{\sqrt{2}}\right) d. (−12,1−12)\left(-\frac{1}{\sqrt{2}}, 1 - \frac{1}{\sqrt{2}}\right)

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