Mathematics

Mathematics

Problem

If x1+y+y1+x=0x\sqrt{1+y} + y\sqrt{1+x} = 0 , then dydx\frac{dy}{dx} equals a. 1(1+x)2\frac{1}{(1+x)^2} b. −1(1+x)2\frac{-1}{(1+x)^2} c. −1(1+x)+1(1+x)2\frac{-1}{(1+x)} + \frac{1}{(1+x)^2} d. None of these

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