Mathematics

Mathematics

Problem

Let the function hh be defined by h(x)={2x2−8x−2,x<2,ln⁡(x−2),x>2.h(x)=\begin{cases} \dfrac{2x^{2}-8}{x-2}, & x<2,\\ \ln(x-2), & x>2. \end{cases} Investigate the limit behavior of hh at x=2x=2 and determine the nature of any discontinuity. a. Part 1: (a) Algebraically simplify the expression 2x2−8x−2\dfrac{2x^{2}-8}{x-2} for x≠2x\ne2, and state the simplified form. b. Part 2: (b) Compute lim⁡x→2−h(x)\displaystyle\lim_{x\to 2^-}h(x) and lim⁡x→2+h(x)\displaystyle\lim_{x\to 2^+}h(x). Clearly indicate any use of the simplified form from part (a). c. Part 3: (c) Identify every vertical asymptote of hh and give a brief justification for each one. d. Part 4: (d) Is hh continuous at x=2x=2? Classify the type of discontinuity that occurs, citing specific numerical evidence from part (b) and relevant limit definitions.

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