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Chemistry
Chemistry
Problem
The cell
Pt
(
H
2
)
(
1
atm
)
∣
H
+
(
pH
=
?
)
∣
∣
I
−
(
a
=
1
)
∣
AgI
(
s
)
,
Ag
(
s
)
∣
Pt
\text{Pt}(\text{H}_2)(1\text{ atm}) | \text{H}^+(\text{pH} = ?) || \text{I}^-(a = 1) | \text{AgI}(\text{s}), \text{Ag}(\text{s}) | \text{Pt}
Pt
(
H
2
)
(
1
atm
)
∣
H
+
(
pH
=
?)
∣∣
I
−
(
a
=
1
)
∣
AgI
(
s
)
,
Ag
(
s
)
∣
Pt
has emf,
E
298
K
=
0
E_{298\text{K}} = 0
E
298
K
=
0
. The standard electrode potential for the reaction
AgI
+
e
−
→
Ag
+
I
−
\text{AgI} + \text{e}^- \rightarrow \text{Ag} + \text{I}^-
AgI
+
e
−
→
Ag
+
I
−
is
−
0.151
volt
-0.151\text{ volt}
−
0.151
volt
. Calculate the pH of anode. (a)
3.37
3.37
3.37
(b)
5.26
5.26
5.26
(c)
2.56
2.56
2.56
(d)
4.62
4.62
4.62
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