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Chemistry
Chemistry
Problem
The precipitate of
CaF
2
\text{CaF}_2
CaF
2
(
K
s
p
=
1.7
×
10
−
10
K_{sp} = 1.7 \times 10^{-10}
K
s
p
=
1.7
×
1
0
−
10
) is obtained when equal volumes of the following are mixed : a.
10
−
4
M
Ca
2
+
10^{-4} M \text{Ca}^{2+}
1
0
−
4
M
Ca
2
+
and
10
−
4
M
F
−
10^{-4} M \text{F}^-
1
0
−
4
M
F
−
b.
10
−
2
M
Ca
2
+
10^{-2} M \text{Ca}^{2+}
1
0
−
2
M
Ca
2
+
and
10
−
3
M
F
−
10^{-3} M \text{F}^-
1
0
−
3
M
F
−
c.
10
−
5
M
Ca
2
+
10^{-5} M \text{Ca}^{2+}
1
0
−
5
M
Ca
2
+
and
10
−
3
M
F
−
10^{-3} M \text{F}^-
1
0
−
3
M
F
−
d.
10
−
3
M
Ca
2
+
10^{-3} M \text{Ca}^{2+}
1
0
−
3
M
Ca
2
+
and
10
−
5
M
F
−
10^{-5} M \text{F}^-
1
0
−
5
M
F
−
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