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Mathematics
Mathematics
Problem
Let
h
:
R
→
R
h:\mathbb{R}\to\mathbb{R}
h
:
R
→
R
be defined by
h
(
x
)
=
⌊
3
x
⌋
−
sgn
(
x
)
h(x)=\lfloor 3x\rfloor-\operatorname{sgn}(x)
h
(
x
)
=
⌊
3
x
⌋
−
sgn
(
x
)
. a. (i) Compute
h
(
−
1.2
)
h(-1.2)
h
(
−
1.2
)
,
h
(
0
)
h(0)
h
(
0
)
and
h
(
2
3
)
h(\dfrac{2}{3})
h
(
3
2
)
. b. (ii) Solve
h
(
x
)
=
4
h(x)=4
h
(
x
)
=
4
for
x
x
x
in the interval
[
0
,
2
]
[0,2]
[
0
,
2
]
. c. (iii) Determine the range of
h
(
x
)
h(x)
h
(
x
)
for
x
∈
[
−
1
,
1
]
x\in[-1,1]
x
∈
[
−
1
,
1
]
. Justify your answer.
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