Prove that tan⁡−1x+tan⁡−11x={π/2,if x>0−π/2,if x<0\text{ Prove that } \tan^{-1}x + \tan^{-1}\frac{1}{x} = \begin{cases} \pi/2, & \text{if } x > 0 \\ -\pi/2, & \text{if } x < 0 \end{cases}

Problem

 Prove that tan⁡−1x+tan⁡−11x={π/2,if x>0−π/2,if x<0\text{ Prove that } \tan^{-1}x + \tan^{-1}\frac{1}{x} = \begin{cases} \pi/2, & \text{if } x > 0 \\ -\pi/2, & \text{if } x < 0 \end{cases}

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