Chemistry

Chemistry

Problem

A laboratory manual provides these enthalpy data (298 K): 1. N2O4(g)→2NO2(g)ΔH1=+58 kJN_{2}O_{4}(g)\rightarrow 2NO_{2}(g)\qquad \Delta H_{1}= +58\,\text{kJ} 2. NO2(g)+CO(g)→NO(g)+CO2(g)ΔH2=−227 kJNO_{2}(g)+CO(g)\rightarrow NO(g)+CO_{2}(g)\qquad \Delta H_{2}= -227\,\text{kJ} 3. N2(g)+O2(g)→2NO(g)ΔH3=+182 kJN_{2}(g)+O_{2}(g)\rightarrow 2NO(g)\qquad \Delta H_{3}= +182\,\text{kJ} 4. CO(g)+12O2(g)→CO2(g)ΔH4=−283 kJCO(g)+\tfrac{1}{2}O_{2}(g)\rightarrow CO_{2}(g)\qquad \Delta H_{4}= -283\,\text{kJ} A student wishes to find the enthalpy change for N2O4(g)+CO(g)→N2(g)+CO2(g)+O2(g)N_{2}O_{4}(g)+CO(g)\rightarrow N_{2}(g)+CO_{2}(g)+O_{2}(g) The student combines Equations 1 and 2 as written and subtracts Equation 3, claiming ΔHrxn=−351 kJ.\Delta H_{\text{rxn}} = -351\,\text{kJ}. After carefully evaluating the steps, which of the following is the correct value of ΔHrxn\Delta H_{\text{rxn}}? a) −351 kJ-351\,\text{kJ} b) −408 kJ-408\,\text{kJ} c) −146 kJ-146\,\text{kJ} d) −292 kJ-292\,\text{kJ}

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