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Chemistry
Chemistry
Problem
For water
Δ
H
vap
=
540
cal g
−
1
\Delta H_{\text{vap}} = 540 \text{ cal g}^{-1}
Δ
H
vap
=
540
cal g
−
1
.
Δ
S
\Delta S
Δ
S
for water at its boiling point
100
∘
C
100^\circ\text{C}
10
0
∘
C
in
cal K
−
1
mol
−
1
\text{cal K}^{-1} \text{ mol}^{-1}
cal K
−
1
mol
−
1
is : a. 540 b. 1.45 c. 26.06 d. 35.60
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