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Mathematics
Mathematics
Problem
If
x
=
sin
−
1
(
3
t
−
4
t
3
)
x = \sin^{-1} (3t - 4t^3)
x
=
sin
−
1
(
3
t
−
4
t
3
)
and
y
=
cos
−
1
(
1
−
t
2
)
y = \cos^{-1} \sqrt{(1-t^2)}
y
=
cos
−
1
(
1
−
t
2
)
,
d
y
d
x
\frac{dy}{dx}
d
x
d
y
is equal to (a)
1
/
2
1/2
1/2
(b)
2
/
5
2/5
2/5
(c)
3
/
2
3/2
3/2
(d)
1
/
3
1/3
1/3
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