Mathematics

Mathematics

Problem

Consider the differential equation dydx=3y2x,x>0,\frac{dy}{dx}=\frac{3y}{2x},\qquad x>0, and the student work shown below attempting to verify that y=kx3/2y=k x^{3/2} is a solution. Student work (with one error): 1. Claim: dydx=3k2x1/2\dfrac{dy}{dx}=\dfrac{3k}{2}x^{1/2}. 2. Substitute into the differential equation: 3k2x1/2=3(kx3/2)2x=3k2x1/2.\dfrac{3k}{2}x^{1/2}=\frac{3(k x^{3/2})}{2x}=\frac{3k}{2}x^{1/2}. 3. Conclude that the function satisfies the differential equation for all x>0x>0. (a) Identify the specific step in the student work that fails to justify the conclusion and clearly describe the error. (b) Provide a complete and correct verification that y=kx3/2y=k x^{3/2} satisfies the differential equation for x>0x>0. (c) Explain why the condition x>0x>0 is essential for the verification in part (b).

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