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Mathematics
Mathematics
Problem
Show that
2
+
2
+
2
+
2
cos
8
θ
=
2
cos
θ
\sqrt{2 + \sqrt{2 + \sqrt{2 + 2 \cos 8\theta}}} = 2 \cos \theta
2
+
2
+
2
+
2
cos
8
θ
=
2
cos
θ
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