Use the commutation relations, eq. (3.29), to show explicitly that a state of the form
∣k1…kn⟩≡a†(k1)…a†(kn)∣0⟩(3.33)
is an eigenstate of the hamiltonian, eq. (3.30), with eigenvalue ω1+…+ωn. The vacuum ∣0⟩ is annihilated by a(k), a(k)∣0⟩=0, and we take Ω0=E0 in eq. (3.30).