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Mathematics
Mathematics
Problem
For
x
x
x
in the domain of the functions, let
h
(
x
)
=
tan
(
3
x
)
cot
(
2
x
)
h(x)=\dfrac{\tan(3x)}{\cot(2x)}
h
(
x
)
=
cot
(
2
x
)
tan
(
3
x
)
. Which of the following is
h
′
(
x
)
h'(x)
h
′
(
x
)
? a)
3
tan
(
2
x
)
sec
2
(
3
x
)
−
2
tan
(
3
x
)
sec
2
(
2
x
)
3\tan(2x)\sec^{2}(3x)-2\tan(3x)\sec^{2}(2x)
3
tan
(
2
x
)
sec
2
(
3
x
)
−
2
tan
(
3
x
)
sec
2
(
2
x
)
b)
3
sec
2
(
3
x
)
+
2
sec
2
(
2
x
)
3\sec^{2}(3x)+2\sec^{2}(2x)
3
sec
2
(
3
x
)
+
2
sec
2
(
2
x
)
c)
3
tan
(
2
x
)
sec
2
(
3
x
)
+
2
tan
(
3
x
)
sec
2
(
2
x
)
3\tan(2x)\sec^{2}(3x)+2\tan(3x)\sec^{2}(2x)
3
tan
(
2
x
)
sec
2
(
3
x
)
+
2
tan
(
3
x
)
sec
2
(
2
x
)
d)
3
tan
(
2
x
)
sec
2
(
3
x
)
+
tan
(
3
x
)
sec
2
(
2
x
)
3\tan(2x)\sec^{2}(3x)+\tan(3x)\sec^{2}(2x)
3
tan
(
2
x
)
sec
2
(
3
x
)
+
tan
(
3
x
)
sec
2
(
2
x
)
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