Mathematics

Mathematics

Problem

△ABC\triangle ABC is right-angled at BB. Another triangle △PQR\triangle PQR is right-angled at QQ. If AB=6 cmAB = 6\,\text{cm}, BC=8 cmBC = 8\,\text{cm}, PR=10 cmPR = 10\,\text{cm} and PQ=6 cmPQ = 6\,\text{cm}, then QRQR equals a) 12 cm12\,\text{cm} b) 7 cm7\,\text{cm} c) 8 cm8\,\text{cm} d) 6 cm6\,\text{cm}

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