Mathematics

Mathematics

Problem

The point P(0,−2)P(0,-2) lies on the curve defined by x=t2−1x=t^{2}-1 and y=t3−3ty=t^{3}-3t. Which is the equation of the normal line to the curve at PP? a) y=−2y=-2 b) x=−2x=-2 c) x=0x=0 d) y=49x−2y=\dfrac{4}{9}x-2

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