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Mathematics
Mathematics
Problem
For the curve
x
=
t
2
+
3
t
,
y
=
t
3
−
3
t
x=t^{2}+3t,\;y=t^{3}-3t
x
=
t
2
+
3
t
,
y
=
t
3
−
3
t
, find the value(s) of
t
t
t
at which the tangent is horizontal. a)
t
=
−
3
2
t=-\dfrac{3}{2}
t
=
−
2
3
b)
t
=
1
t=1
t
=
1
only c)
t
=
±
1
t=\pm 1
t
=
±
1
d)
t
=
0
t=0
t
=
0
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