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Physics
Physics
Problem
A simple pendulum is set oscillating with a small angular amplitude
θ
1
\theta_1
θ
1
. If the amplitude is doubled to
θ
2
=
2
θ
1
\theta_2 = 2\theta_1
θ
2
=
2
θ
1
(still within the small-angle limit), what happens to its time period? a)
2
T
2T
2
T
b)
2
T
\sqrt{2}\,T
2
T
c) It remains practically unchanged (
T
T
T
) d)
T
2
\dfrac{T}{2}
2
T
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