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Problem
Problem
In
△
A
B
C
\triangle ABC
△
A
B
C
,
a
=
4
a = 4
a
=
4
,
b
=
12
b = 12
b
=
12
and
B
=
60
∘
B = 60^\circ
B
=
6
0
∘
, then the value of
sin
A
\sin A
sin
A
is a.
1
2
3
\frac{1}{2\sqrt{3}}
2
3
1
b.
1
3
2
\frac{1}{3\sqrt{2}}
3
2
1
c.
2
3
\frac{2}{\sqrt{3}}
3
2
d.
3
2
\frac{\sqrt{3}}{2}
2
3
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