An Introduction To Quantum Field Theory - M. Peskin, D. Schroeder (Perseus, 1995) · Problem 18.2

Operator Products and Effective Vertices — M. Peskin, D. Schroeder (Perseus, 1995)

Physics — QFT · operator-products-effective-vertices

Problem

Parity-violating deep inelastic form factor. In this problem, we first motivate the presence of additional deep inelastic form factors that are proportional to *differences* of quark and antiquark distribution functions. Then we define these functions formally and work out their properties. (a) Analyze neutrino-proton scattering following the method used at the beginning of Section 18.5. Define J+μ=uˉγμ(1−γ52)d,J−μ=dˉγμ(1−γ52)u.J_+^\mu = \bar{u}\gamma^\mu\left(\frac{1-\gamma^5}{2}\right)d, \qquad J_-^\mu = \bar{d}\gamma^\mu\left(\frac{1-\gamma^5}{2}\right)u. Let Wμν(ν)=2i∫d4x eiq⋅x⟨P∣ T{J−μ(x)J+ν(0)} ∣P⟩,W^{\mu\nu(\nu)} = 2i \int d^4x\, e^{iq\cdot x} \langle P|\, T\{J_-^\mu(x) J_+^\nu(0)\}\,|P\rangle, averaged over the proton spin. Show that the cross section for deep inelastic neutrino scattering can be computed from Wμν(ν)W^{\mu\nu(\nu)} according to d2σdxdy(νp→μ−X)=GF2y2π2⋅Im[(kμkν′+kνkμ′−gμνk⋅k′−iϵμναβkα′kβ)Wμν(ν)(P,q)].\frac{d^2\sigma}{dxdy}(\nu p \to \mu^- X) = \frac{G_F^2 y}{2\pi^2} \cdot \mathbf{Im}\big[(k_\mu k'_\nu + k_\nu k'_\mu - g_{\mu\nu} k\cdot k' - i\epsilon_{\mu\nu}{}^{\alpha\beta} k'_\alpha k_\beta) W^{\mu\nu(\nu)}(P,q)\big]. (b) Show that any term in Wμν(ν)W^{\mu\nu(\nu)} proportional to qμq^\mu or qνq^\nu gives zero when contracted with the lepton momentum tensor in the formula above. Thus we can expand Wμν(ν)W^{\mu\nu(\nu)} with three scalar form factors, Wμν(ν)=−gμνW1(ν)+PμPνW2(ν)+iϵμνλσPλqσW3(ν)+⋯ ,W^{\mu\nu(\nu)} = -g^{\mu\nu} W_1^{(\nu)} + P^\mu P^\nu W_2^{(\nu)} + i\epsilon^{\mu\nu\lambda\sigma} P_\lambda q_\sigma W_3^{(\nu)} + \cdots, where the additional terms do not contribute to the deep inelastic cross section. Find the formula for the deep inelastic cross section in terms of the imaginary parts of W1(ν)W_1^{(\nu)}, W2(ν)W_2^{(\nu)}, and W3(ν)W_3^{(\nu)}. (c) Evaluate the form factors Wi(ν)W_i^{(\nu)} in the parton model, and show that Im W1(ν)=π(fd(x)+fuˉ(x)),\mathrm{Im}\, W_1^{(\nu)} = \pi(f_d(x) + f_{\bar{u}}(x)), Im W2(ν)=4πysx(fd(x)+fuˉ(x)),\mathrm{Im}\, W_2^{(\nu)} = \frac{4\pi}{ys} x(f_d(x) + f_{\bar{u}}(x)), Im W3(ν)=2πys(fd(x)−fuˉ(x)).\mathrm{Im}\, W_3^{(\nu)} = \frac{2\pi}{ys}(f_d(x) - f_{\bar{u}}(x)). Insert these expressions into the formula derived in part (b) and show that the result reproduces the first line of Eq. (17.35). (d) This analysis motivates the following definition: For a single quark flavor ff, let JfLμ=fˉγμ(1−γ52)f.J_{fL}^\mu = \bar{f}\gamma^\mu\left(\frac{1-\gamma^5}{2}\right)f. Define WfLμν=2i∫d4x eiq⋅x⟨P∣ T{JfLμ(x)JfLν(0)} ∣P⟩.W_{fL}^{\mu\nu} = 2i \int d^4x\, e^{iq\cdot x} \langle P|\,T\{J_{fL}^\mu(x) J_{fL}^\nu(0)\}\,|P\rangle. Decompose this tensor according to WfLμν=−gμνW1fL+PμPνW2fL+iϵμνλσPλqσW3fL+⋯ ,W_{fL}^{\mu\nu} = -g^{\mu\nu} W_{1fL} + P^\mu P^\nu W_{2fL} + i\epsilon^{\mu\nu\lambda\sigma} P_\lambda q_\sigma W_{3fL} + \cdots, where the remaining terms are proportional to qμq^\mu or qνq^\nu. Evaluate the WiLW_{iL} in the parton model. Show that the quantities W1fLW_{1fL} and W2fLW_{2fL} reproduce the expressions for W1fW_{1f} and W2fW_{2f} given by Eqs. (18.120) and (18.144), and that W3fLW_{3fL} is given by Im W3fL=2πys(ff(x)−ffˉ(x)).\mathrm{Im}\, W_{3fL} = \frac{2\pi}{ys}(f_f(x) - f_{\bar{f}}(x)). (e) Compute the operator product of the currents in the expression for WfLμνW_{fL}^{\mu\nu}, and write the terms in this product that involve twist-2 operators. Show that the expressions for W1fLW_{1fL} and W2fLW_{2fL} that follow from this analysis reproduce the expressions for W1fW_{1f} and W2fW_{2f} given by Eqs. (18.144) and (18.145). Find the corresponding expression for W3fLW_{3fL}. (f) Define the parton distribution ff−f_f^- by the relation ff−(x,Q2)=ys2π Im W3fL(x,Q2).f_f^-(x, Q^2) = \frac{ys}{2\pi}\,\mathrm{Im}\, W_{3fL}(x, Q^2). Show that, by virtue of this definition, the distribution function ff−f_f^- satisfies the sum rule (18.155) for odd nn.

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