Canonical Quantization of Scalar Fields — Mark Srednicki
Physics — QFT · interaction-picture-derivation
Problem
The interaction picture. In this problem, we will derive a formula for ⟨0∣Tφ(xn)…φ(x1)∣0⟩ without using path integrals. Suppose we have a hamiltonian density H=H0+H1, where H0=21Π2+21(∇φ)2+21m2φ2, and H1 is a function of Π(x,0) and φ(x,0) and their spatial derivatives. (It should be chosen to preserve Lorentz invariance, but we will not be concerned with this issue.) We add a constant to H so that H∣0⟩=0. Let ∣∅⟩ be the ground state of H0, with a constant added to H0 so that H0∣∅⟩=0. (H1 is then defined as H−H0.) The Heisenberg-picture field is
φ(x,t)≡eiHtφ(x,0)e−iHt.(9.33)
We now define the interaction-picture field
φI(x,t)≡eiH0tφ(x,0)e−iH0t.(9.34)
a) Show that φI(x) obeys the Klein-Gordon equation, and hence is a free field.
b) Show that φ(x)=U†(t)φI(x)U(t), where U(t)≡eiH0te−iHt is unitary.
c) Show that U(t) obeys the differential equation idtdU(t)=HI(t)U(t), where HI(t)=eiH0tH1e−iH0t is the interaction hamiltonian in the interaction picture, and the boundary condition U(0)=1.
d) If H1 is specified by a particular function of the Schr\"odinger-picture fields Π(x,0) and φ(x,0), show that HI(t) is given by the same function of the interaction-picture fields ΠI(x,t) and φI(x,t).
e) Show that, for t>0,
U(t)=Texp[−i∫0tdt′HI(t′)](9.35)
obeys the differential equation and boundary condition of part (c). What is the comparable expression for t<0? Hint: you may need to define a new ordering symbol.
f) Define U(t2,t1)≡U(t2)U†(t1). Show that, for t2>t1,
U(t2,t1)=Texp[−i∫t1t2dt′HI(t′)].(9.36)
What is the comparable expression for t1>t2?
g) For any time ordering, show that U(t3,t1)=U(t3,t2)U(t2,t1) and that U†(t1,t2)=U(t2,t1).
h) Show that
φ(xn)…φ(x1)=U†(tn,0)φI(xn)U(tn,tn−1)φI(xn−1)…U(t2,t1)φI(x1)U(t1,0).(9.37)
i) Show that U†(tn,0)=U†(∞,0)U(∞,tn) and also that U(t1,0)=U(t1,−∞)U(−∞,0).
j) Replace H0 with (1−iϵ)H0, and show that ⟨0∣U†(∞,0)=⟨0∣∅⟩⟨∅∣ and that U(−∞,0)∣0⟩=∣∅⟩⟨∅∣0⟩.
k) Show that
⟨0∣φ(xn)…φ(x1)∣0⟩=⟨∅∣U(∞,tn)φI(xn)U(tn,tn−1)φI(xn−1)…U(t2,t1)φI(x1)U(t1,−∞)∣∅⟩×∣⟨∅∣0⟩∣2.(9.38)
l) Show that
⟨0∣Tφ(xn)…φ(x1)∣0⟩=⟨∅∣TφI(xn)…φI(x1)e−i∫d4xHI(x)∣∅⟩×∣⟨∅∣0⟩∣2.(9.39)
m) Show that
∣⟨∅∣0⟩∣2=1/⟨∅∣Te−i∫d4xHI(x)∣∅⟩.(9.40)
Thus we have
⟨0∣Tφ(xn)…φ(x1)∣0⟩=⟨∅∣Te−i∫d4xHI(x)∣∅⟩⟨∅∣TφI(xn)…φI(x1)e−i∫d4xHI(x)∣∅⟩.(9.41)