Mathematics

Mathematics

Problem

Let f:[0,2]→Rf: [0, 2] \to \mathbb{R} be a function which is continuous on [0,2][0, 2] and is differentiable on (0,2)(0, 2) with f(0)=1f(0) = 1 . Let F(x)=∫0x2f(t)dtfor x∈[0,2].F(x) = \int_{0}^{x^2} f(\sqrt{t}) dt \quad \text{for } x \in [0, 2]. If F′(x)=f′(x)F'(x) = f'(x) for all x∈(0,2)x \in (0, 2) , then F(2)F(2) equals [JEE(Advanced) 2014] (A) e2−1e^2 - 1 (B) e4−1e^4 - 1 (C) e−1e - 1 (D) e4e^4

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