Let f:R→R be given by f(x)=∣ax+b∣, where a=0 and b are real constants.
a. (i) Explain why the range of f is [0,∞).
b. (ii) State the condition on a and b under which f(x)=0 has a solution, and find that solution.
c. (iii) If the domain of f is restricted to x≥−ab, determine the new range of f and justify your result.