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Blundell Thermal Physics
· Problem 1.6
Introduction
Physics — Statistical Mechanics · stirlings-approximation
Problem
Show that eqn C.19 is equivalent to writing
n
!
≈
n
n
e
−
n
2
π
n
,
(1.21)
n! \approx n^n e^{-n} \sqrt{2\pi n},\tag{1.21}
n
!
≈
n
n
e
−
n
2
π
n
,
(
1.21
)
and
n
!
≈
2
π
n
n
+
1
2
e
−
n
.
(1.22)
n! \approx \sqrt{2\pi}\, n^{n+\frac{1}{2}} e^{-n}.\tag{1.22}
n
!
≈
2
π
n
n
+
2
1
e
−
n
.
(
1.22
)
Related theory
Approximation Algorithms And The Approximation Ratio
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