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Mathematics
Problem
A particle moves along a straight line with velocity
v
(
t
)
=
4
t
2
−
3
t
−
2
v(t)=4t^{2}-3t-2
v
(
t
)
=
4
t
2
−
3
t
−
2
feet per second for
1
≤
t
≤
3
1\le t\le 3
1
≤
t
≤
3
. Determine the particle’s displacement, in feet, over this interval. a)
33
2
\displaystyle \frac{33}{2}
2
33
b)
43
3
\displaystyle \frac{43}{3}
3
43
c)
56
3
\displaystyle \frac{56}{3}
3
56
d)
16
16
16
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