Chemistry

Chemistry

Problem

Two identical neutralization reactions are carried out in separate calorimeters that differ only in their calorimeter constants: Ccal,A=20 J ∘ ⁣C−1C_{\text{cal,A}} = 20\,\text{J}\,^\circ\!\text{C}^{-1} and Ccal,B=80 J ∘ ⁣C−1C_{\text{cal,B}} = 80\,\text{J}\,^\circ\!\text{C}^{-1}. All other experimental conditions (masses, concentrations, and heat released) are the same. Which statement correctly compares the temperature changes ΔTA\Delta T_A and ΔTB\Delta T_B observed during the experiments? a) ΔTA<ΔTB\Delta T_A < \Delta T_B because calorimeter A absorbs more heat than calorimeter B. b) ΔTA=ΔTB\Delta T_A = \Delta T_B because both reactions release the same quantity of heat. c) ΔTA>ΔTB\Delta T_A > \Delta T_B because less heat is required to raise the temperature of calorimeter A. d) ΔTB=4 ΔTA\Delta T_B = 4\,\Delta T_A because calorimeter B\,'s heat capacity is four times that of calorimeter A.

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