Physics

Problem

The ends of a stretched wire of length

L

are fixed at

x = 0

and

x = L

. In one experiment, the displacement of the wire is

y_1 = A \sin (\pi x/L) \sin \omega t

and energy is

E_1

and in another experiment its displacement is

y_2 = A \sin (2\pi x/L) \sin 2\omega t

and energy is

E_2

. Then a.

E_2 = E_1

E_2 = 2E_1

E_2 = 4E_1

E_2 = 16E_1