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Physics
Problem
Which of the following relations correctly gives the equivalent resistance
R
eq
R_{\text{eq}}
R
eq
of three resistors
R
1
,
R
2
R_1,\;R_2
R
1
,
R
2
and
R
3
R_3
R
3
connected in parallel? a)
R
eq
=
R
1
R
2
+
R
2
R
3
+
R
3
R
1
R
1
+
R
2
+
R
3
\displaystyle R_{\text{eq}}=\frac{R_1R_2+R_2R_3+R_3R_1}{R_1+R_2+R_3}
R
eq
=
R
1
+
R
2
+
R
3
R
1
R
2
+
R
2
R
3
+
R
3
R
1
b)
R
eq
=
R
1
+
R
2
+
R
3
R_{\text{eq}}=R_1+R_2+R_3
R
eq
=
R
1
+
R
2
+
R
3
c)
1
R
eq
=
1
R
1
+
1
R
2
+
1
R
3
\displaystyle \frac{1}{R_{\text{eq}}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}
R
eq
1
=
R
1
1
+
R
2
1
+
R
3
1
d)
R
eq
=
R
1
R
2
R
3
3
\displaystyle R_{\text{eq}}=\sqrt[3]{R_1R_2R_3}
R
eq
=
3
R
1
R
2
R
3
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