Problem

Problem

Which step(s) is/are endothermic in the Born–Haber cycle for the formation of LiCl? a. 12Cl2(g)→Cl(g)\frac{1}{2}\text{Cl}_2(\text{g}) \rightarrow \text{Cl}(\text{g}) and Li(s)→Li(g)\text{Li}(\text{s}) \rightarrow \text{Li}(\text{g}) b. Cl(g)+e−→Cl−(g)\text{Cl}(\text{g}) + \text{e}^- \rightarrow \text{Cl}^-(\text{g}) and Li(g)→Li+(g)+e−\text{Li}(\text{g}) \rightarrow \text{Li}^+(\text{g}) + \text{e}^- c. Li+(g)+Cl−(g)→LiCl(s)\text{Li}^+(\text{g}) + \text{Cl}^-(\text{g}) \rightarrow \text{LiCl}(\text{s}) d. 12Cl2(g)→Cl(g)\frac{1}{2}\text{Cl}_2(\text{g}) \rightarrow \text{Cl}(\text{g}) and Cl(g)+e−→Cl−(g)\text{Cl}(\text{g}) + \text{e}^- \rightarrow \text{Cl}^-(\text{g})

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