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Problem Let y = ( sin x ) cos x y=(\sin x)^{\cos x} y = ( sin x ) c o s x for x ∈ ( 0 , π 2 ) x\in\left(0,\dfrac{\pi}{2}\right) x ∈ ( 0 , 2 π ) . The value of d y d x \dfrac{dy}{dx} d x d y at x = π 4 x=\dfrac{\pi}{4} x = 4 π is
a) ( sin π 4 ) cos π 4 [ 2 4 ln 2 + 2 4 ] (\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[\dfrac{\sqrt{2}}{4}\,\ln 2+\dfrac{\sqrt{2}}{4}\right] ( sin 4 π ) c o s 4 π [ 4 2 ln 2 + 4 2 ]
b) ( sin π 4 ) cos π 4 [ 2 4 ln 2 + 1 2 ] (\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[\dfrac{\sqrt{2}}{4}\,\ln 2+\dfrac{1}{\sqrt{2}}\right] ( sin 4 π ) c o s 4 π [ 4 2 ln 2 + 2 1 ]
c) ( sin π 4 ) cos π 4 [ − 2 4 ln 2 + 1 2 ] (\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[-\dfrac{\sqrt{2}}{4}\,\ln 2+\dfrac{1}{\sqrt{2}}\right] ( sin 4 π ) c o s 4 π [ − 4 2 ln 2 + 2 1 ]
d) ( sin π 4 ) cos π 4 [ 2 4 ln 2 + 1 ] (\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[\dfrac{\sqrt{2}}{4}\,\ln 2+1\right] ( sin 4 π ) c o s 4 π [ 4 2 ln 2 + 1 ]
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