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JEE Advanced 2012 Paper 1 Chemistry Q20
Chemistry · Chemical Kinetics
Problem
An organic compound undergoes first-order decomposition. The time taken for its decomposition to
1
/
8
1/8
1/8
and
1
/
10
1/10
1/10
of its initial concentration are
t
1
/
8
t_{1/8}
t
1/8
and
t
1
/
10
t_{1/10}
t
1/10
respectively. What is the value of
[
t
1
/
8
t
1
/
10
]
×
10
\left[\dfrac{t_{1/8}}{t_{1/10}}\right]\times10
[
t
1/10
t
1/8
]
×
10
? (take
log
10
2
=
0.3
\log_{10}2=0.3
lo
g
10
2
=
0.3
)
Related theory
Chemical Kinetics
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