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Mathematics
Mathematics
Problem
A curve
g
(
x
)
=
∫
x
27
(
1
+
x
+
x
2
)
4
(
6
x
2
+
5
x
+
4
)
d
x
g(x) = \int x^{27} (1+x+x^2)^4 (6x^2+5x+4)\,dx
g
(
x
)
=
∫
x
27
(
1
+
x
+
x
2
)
4
(
6
x
2
+
5
x
+
4
)
d
x
is passing through origin. Then (a)
g
(
1
)
=
3
7
7
g(1) = \frac{3^7}{7}
g
(
1
)
=
7
3
7
(b)
g
(
1
)
=
2
7
7
g(1) = \frac{2^7}{7}
g
(
1
)
=
7
2
7
(c)
g
(
−
1
)
=
1
7
g(-1) = \frac{1}{7}
g
(
−
1
)
=
7
1
(d)
g
(
−
1
)
=
3
7
14
g(-1) = \frac{3^7}{14}
g
(
−
1
)
=
14
3
7
(a)
g
(
1
)
=
3
7
7
g(1) = \frac{3^7}{7}
g
(
1
)
=
7
3
7
(b)
g
(
1
)
=
2
7
7
g(1) = \frac{2^7}{7}
g
(
1
)
=
7
2
7
(c)
g
(
−
1
)
=
1
7
g(-1) = \frac{1}{7}
g
(
−
1
)
=
7
1
(d)
g
(
−
1
)
=
3
7
14
g(-1) = \frac{3^7}{14}
g
(
−
1
)
=
14
3
7
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