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Problem
Problem
Let
V
V
V
be the vertex and
L
L
L
be the latusrectum of the parabola
x
2
=
2
y
+
4
x
−
4
x^2 = 2y + 4x - 4
x
2
=
2
y
+
4
x
−
4
. Then, the equation of the parabola whose vertex is at
V
V
V
, latusrectum
L
/
2
L/2
L
/2
and axis is perpendicular to the axis of the given parabola. a.
y
2
=
x
−
2
y^2 = x - 2
y
2
=
x
−
2
b.
y
2
=
x
−
4
y^2 = x - 4
y
2
=
x
−
4
c.
y
2
=
2
−
x
y^2 = 2 - x
y
2
=
2
−
x
d.
y
2
=
4
−
x
y^2 = 4 - x
y
2
=
4
−
x
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