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Mathematics
Problem
If
tan
−
1
a
+
x
a
+
tan
−
1
a
−
x
a
=
π
6
\tan^{-1} \frac{a+x}{a} + \tan^{-1} \frac{a-x}{a} = \frac{\pi}{6}
tan
−
1
a
a
+
x
+
tan
−
1
a
a
−
x
=
6
π
, then
x
2
=
x^2 =
x
2
=
(a)
2
3
a
2\sqrt{3} a
2
3
a
(b)
3
a
\sqrt{3} a
3
a
(c)
2
3
a
2
2\sqrt{3} a^2
2
3
a
2
(d) None of these
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