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Mathematics
Problem
A company’s revenue (in thousand rupees) from selling
x
x
x
units is
R
(
x
)
=
50
x
−
x
2
2
R(x)=50x-\dfrac{x^{2}}{2}
R
(
x
)
=
50
x
−
2
x
2
for
0
≤
x
≤
30
0\le x\le30
0
≤
x
≤
30
. Determine the production level that yields the highest revenue on this interval and state the corresponding maximum revenue.
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