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Mathematics
Problem
Find
d
d
x
[
x
3
+
2
x
x
−
1
]
\dfrac{d}{dx}\left[\dfrac{x^{3}+2x}{x-1}\right]
d
x
d
[
x
−
1
x
3
+
2
x
]
. a)
2
x
3
−
3
x
2
−
2
x
−
1
\dfrac{2x^{3}-3x^{2}-2}{x-1}
x
−
1
2
x
3
−
3
x
2
−
2
b)
2
x
3
−
3
x
2
−
2
(
x
−
1
)
2
\dfrac{2x^{3}-3x^{2}-2}{(x-1)^{2}}
(
x
−
1
)
2
2
x
3
−
3
x
2
−
2
c)
3
x
2
+
2
x
−
1
\dfrac{3x^{2}+2}{x-1}
x
−
1
3
x
2
+
2
d)
−
2
x
3
+
3
x
2
+
2
(
x
−
1
)
2
\dfrac{-2x^{3}+3x^{2}+2}{(x-1)^{2}}
(
x
−
1
)
2
−
2
x
3
+
3
x
2
+
2
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