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Mathematics
Mathematics
Problem
Statement I
Number of roots of the equation
cot
−
1
x
cos
−
1
2
x
+
π
=
0
\cot^{-1} x \cos^{-1} 2x + \pi = 0
cot
−
1
x
cos
−
1
2
x
+
π
=
0
is zero.
Statement II
Range of
cot
−
1
x
\cot^{-1} x
cot
−
1
x
and
cos
−
1
x
\cos^{-1} x
cos
−
1
x
is
(
0
,
π
)
(0, \pi)
(
0
,
π
)
and
[
0
,
π
]
[0, \pi]
[
0
,
π
]
, respectively.
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