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Chemistry
Chemistry
Problem
Calculate
Δ
H
f
∘
\Delta H_f^\circ
Δ
H
f
∘
for chloride ion from the following data :
1
2
H
2
(
g
)
+
1
2
C
l
2
(
g
)
⟶
H
C
l
(
g
)
;
Δ
H
f
∘
=
−
92.4
kJ
\frac{1}{2}H_2(g) + \frac{1}{2}Cl_2(g) \longrightarrow HCl(g); \quad \Delta H_f^\circ = -92.4 \text{ kJ}
2
1
H
2
(
g
)
+
2
1
C
l
2
(
g
)
⟶
H
C
l
(
g
)
;
Δ
H
f
∘
=
−
92.4
kJ
H
C
l
(
g
)
+
n
H
2
O
⟶
H
+
(
a
q
.
)
+
C
l
−
(
a
q
.
)
;
Δ
H
f
∘
=
−
748
kJ
HCl(g) + nH_2O \longrightarrow H^+(aq.) + Cl^-(aq.); \quad \Delta H_f^\circ = -748 \text{ kJ}
H
C
l
(
g
)
+
n
H
2
O
⟶
H
+
(
a
q
.
)
+
C
l
−
(
a
q
.
)
;
Δ
H
f
∘
=
−
748
kJ
Δ
H
f
∘
H
+
(
a
q
.
)
=
0.0
kJ
\Delta H_f^\circ H^+(aq.) = 0.0 \text{ kJ}
Δ
H
f
∘
H
+
(
a
q
.
)
=
0.0
kJ
(Roorkhee 1992)
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