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Mathematics
Mathematics
Problem
Let
y
=
(
1
+
2
p
x
)
4
y=(1+2px)^{4}
y
=
(
1
+
2
p
x
)
4
, where
p
p
p
is a positive constant. If
d
2
y
d
x
2
∣
x
=
0
=
96
\displaystyle \left.\dfrac{d^{2}y}{dx^{2}}\right|_{x=0}=96
d
x
2
d
2
y
x
=
0
=
96
, then
p
p
p
equals a)
4
4
4
b)
2
2
2\sqrt{2}
2
2
c)
2
\sqrt{2}
2
d)
2
2
\dfrac{\sqrt{2}}{2}
2
2
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